【例题】先化简,再求值:\(\displaystyle \left( {2-a} \right)\left( {2+a} \right)-2a\left( {a+3} \right)+3{{a}^{2}}\),其中\(\displaystyle a=-\frac{1}{3}\)
【答案】4-6a,6
【解析】\(\displaystyle \left( {2-a} \right)\left( {2+a} \right)-2a\left( {a+3} \right)+3{{a}^{2}}\)
\(\displaystyle =4-{{a}^{2}}-2{{a}^{2}}-6a+3{{a}^{2}}\)
\(\displaystyle =4-6a\)
【解题技巧】括号前面为负号,去括号时必变号。
